You are handed \tfrac{5}{8} and \tfrac{7}{11} and asked which is bigger. The textbook method is to find the LCM of 8 and 11, rewrite both fractions over 88, and compare the numerators. That works, but it is four steps and a multiplication table. There is a one-line shortcut that gives the same answer in three seconds, and every competitive-exam problem-solver has it on autopilot.

The trick

To compare two positive fractions \dfrac{a}{b} and \dfrac{c}{d}, cross-multiply:

The bigger of those two products tells you which fraction is bigger.

Apply it to \tfrac{5}{8} vs \tfrac{7}{11}:

Since 56 > 55, the right-hand fraction \tfrac{7}{11} is bigger. Done — one multiplication on each side, one comparison, one answer.

Cross multiplication diagram for comparing five eighths and seven eleventhsTwo fractions five over eight and seven over eleven placed side by side. Two diagonal arrows cross between them. One arrow labels five times eleven equals fifty-five connecting the five on the left top to the eleven on the right bottom. The other arrow labels eight times seven equals fifty-six connecting the eight on the left bottom to the seven on the right top. The second product fifty-six is larger and is highlighted, indicating seven elevenths is the bigger fraction. 5 8 vs 7 11 5 × 11 = 55 8 × 7 = 56 ← larger so 7/11 > 5/8
The two diagonal products are $5 \times 11 = 55$ and $8 \times 7 = 56$. The bigger product comes from the diagonal that includes the $7$ (on the right), so $\tfrac{7}{11}$ is the bigger fraction. The entire comparison is two multiplications and one inequality — no LCM, no rewriting.

Why this works

The fraction \dfrac{a}{b} is really \dfrac{a \times d}{b \times d} and the fraction \dfrac{c}{d} is really \dfrac{c \times b}{d \times b}. Both are now written over the same (positive) denominator bd, so comparing them reduces to comparing their numerators: ad versus bc.

Why: any two positive fractions can be given the common denominator bd in one move — multiply each top and bottom by the other fraction's denominator. Once they share a denominator, the fraction with the bigger numerator is the bigger number. The cross-products ad and bc are exactly those numerators over the shared denominator bd.

So cross-multiplication is not a trick — it is the standard "find a common denominator" method, with the rewriting step skipped because you only need the numerators to compare, not the fractions themselves.

One warning: positive denominators only

Cross-multiplication reverses if one of the denominators is negative, because multiplying an inequality by a negative number flips it. Every fraction you will meet in a school exam has a positive denominator (the convention is to put the minus sign in the numerator, e.g. \tfrac{-3}{5} rather than \tfrac{3}{-5}), so this does not come up in practice. But if you ever see \tfrac{a}{b} with b < 0, rewrite it as \tfrac{-a}{|b|} before cross-multiplying.

Try it — drag and compare

Interactive cross multiplication comparison with draggable numerators and denominatorsA horizontal number line from one to twenty with four draggable red points labelled a, b, c, d. Readouts above the line show the two cross products a times d and b times c, and a verdict line that says which fraction is larger as the reader drags the four points. The readouts update live so students can experiment with many different fraction pairs. if a×d > b×c then a/b > c/d, otherwise c/d is bigger 1 10 20 ↔ drag any point
Drag the four points to change $a$, $b$, $c$, $d$. The two readouts show the cross-products $a \times d$ and $b \times c$. Whichever is larger tells you which of $\tfrac{a}{b}$ and $\tfrac{c}{d}$ is larger — no common denominator required. Try it on a few JEE-style pairs and notice how quickly the answer pops out.

Three exam-style uses

Comparing two fractions in an MCQ. Options list \tfrac{13}{17} and \tfrac{15}{19} — which is bigger? Cross-multiply: 13 \times 19 = 247, 17 \times 15 = 255. 255 wins, so \tfrac{15}{19} is bigger.

Comparing a fraction to an integer or to \tfrac{1}{2}. Is \tfrac{4}{9} > \tfrac{1}{2}? Cross-multiply: 4 \times 2 = 8, 9 \times 1 = 9. 9 > 8, so \tfrac{1}{2} is bigger. (In general, \tfrac{a}{b} > \tfrac{1}{2} exactly when 2a > b — the doubled numerator beats the denominator. Useful for a quick sniff test on probability answers.)

Ranking three fractions. Given \tfrac{3}{5}, \tfrac{4}{7}, \tfrac{5}{9}, rank them. Compare pairs. \tfrac{3}{5} vs \tfrac{4}{7}: 3 \times 7 = 21, 5 \times 4 = 20. So \tfrac{3}{5} > \tfrac{4}{7}. \tfrac{4}{7} vs \tfrac{5}{9}: 4 \times 9 = 36, 7 \times 5 = 35. So \tfrac{4}{7} > \tfrac{5}{9}. By transitivity, \tfrac{3}{5} > \tfrac{4}{7} > \tfrac{5}{9}.

Near-ties: when cross-products are close

If ad and bc come out very close — like 55 and 56 in the opening example — the fractions are also very close. That is worth knowing, because it tells you when a problem is asking you to distinguish small differences and you need to be careful. Specifically, the difference between the two fractions is

\frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd}

so if the cross-products differ by just 1 and the denominator product bd is large (say, 88), the fractions differ by only \tfrac{1}{88} \approx 0.011. Your intuition should register this as "these two are almost the same, and I should double-check the cross-multiplication before committing."

What to remember

One simple rule; dozens of exam questions reduced to two multiplications. This is the cheapest comparison tool in your mental toolkit, and it belongs on autopilot.

Related: Fractions and Decimals · What's the Quickest Way to Compare 7/9 and 11/15 in My Head? · Is 0.45 Bigger Than 0.8 Because It Has More Digits? · Can I Add 1/2 + 1/3 by Adding Tops and Bottoms to Get 2/5?