In short

The modulus of a complex number z = x + yi is |z| = \sqrt{x^2 + y^2}. It measures the distance from z to the origin on the complex plane. The modulus is always a non-negative real number. It respects multiplication (|z_1 z_2| = |z_1||z_2|) and division (|z_1/z_2| = |z_1|/|z_2|). The central result is the triangle inequality: |z_1 + z_2| \leq |z_1| + |z_2|, which says the direct path is never longer than the detour.

A real number has a size: its absolute value. The absolute value of -7 is 7. The absolute value of 3 is 3. It measures how far the number is from zero on the number line.

A complex number lives on a plane, not a line. The number 3 + 4i has two components — a real part 3 and an imaginary part 4 — and its position on the complex plane is the point (3, 4). The distance from this point to the origin (0, 0) is the modulus of 3 + 4i.

That distance is \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

The modulus is the complex-number version of the absolute value. It answers the question: how far is this number from zero?

The definition

Modulus of a complex number

If z = x + yi where x, y \in \mathbb{R}, the modulus (or absolute value) of z is

|z| = \sqrt{x^2 + y^2}.

The modulus is a non-negative real number. It equals zero if and only if z = 0.

The formula is the Pythagorean theorem applied to the right triangle with legs x and y on the complex plane. The real part x is the horizontal distance, the imaginary part y is the vertical distance, and |z| is the hypotenuse.

Modulus of 3 plus 4i as the hypotenuse of a right triangleA complex plane with a right triangle drawn from the origin to the point (3, 4). The horizontal leg along the real axis has length 3. The vertical leg has length 4. The hypotenuse from the origin to the point (3, 4) has length 5, which is the modulus. The right angle at (3, 0) is marked with a small square.ReIm01234123z = 3 + 4i3(real part)4(imaginary part)|z| = 5hypotenuse
The modulus of $z = 3 + 4i$ is the distance from the origin to the point $(3, 4)$. By the Pythagorean theorem, $|z| = \sqrt{3^2 + 4^2} = 5$. The horizontal leg is the real part, the vertical leg is the imaginary part, and the modulus is the hypotenuse.

A few immediate examples:

|5 + 12i| = \sqrt{25 + 144} = \sqrt{169} = 13
|1 - i| = \sqrt{1 + 1} = \sqrt{2}
|4i| = \sqrt{0 + 16} = 4
|-7| = \sqrt{49 + 0} = 7

That last one confirms: for a real number a, the modulus |a + 0i| = \sqrt{a^2} = |a|. The complex modulus reduces to the ordinary absolute value when the imaginary part is zero.

Connection to the conjugate

You saw in Algebra of Complex Numbers that z \cdot \bar{z} = x^2 + y^2 for z = x + yi. That product is the square of the modulus:

z \cdot \bar{z} = |z|^2

This identity is one of the most useful in all of complex number theory. It connects three ideas — the modulus, the conjugate, and multiplication — in a single equation. You have already used it to make division work (the denominator in Division of Complex Numbers is |z_2|^2 = z_2 \bar{z_2}), and you used it to find square roots (the modulus equation in the method of comparison is x^2 + y^2 = |z|).

A complex number z and its conjugate z-bar sharing the same modulusA complex plane with two points: z at (3, 2) above the real axis and z-bar at (3, negative 2) below it. Both are at the same distance from the origin, shown by two equal-length arrows from (0,0). A circle of radius equal to the modulus is drawn centred at the origin, passing through both points.ReIm012341−1z = 3 + iz̄ = 3 − i|z| = √10|z̄| = √10circle of radius √10
The complex number $z = 3 + i$ and its conjugate $\bar{z} = 3 - i$ sit on a circle of radius $|z| = \sqrt{10}$ centred at the origin. Conjugation reflects a point across the real axis without changing its distance from the origin: $|z| = |\bar{z}|$ always.

Properties of the modulus

The modulus satisfies a set of clean algebraic properties. Each one has both an algebraic proof (compute with x and y) and a geometric interpretation (think about distances and directions on the complex plane).

1. Non-negativity. |z| \geq 0, and |z| = 0 if and only if z = 0.

This is immediate: x^2 + y^2 \geq 0, and it equals zero only when both x = 0 and y = 0.

2. Conjugate symmetry. |\bar{z}| = |z|.

Since \bar{z} = x - yi, |\bar{z}| = \sqrt{x^2 + (-y)^2} = \sqrt{x^2 + y^2} = |z|. Geometrically, reflection across the real axis does not change the distance from the origin.

3. Multiplicativity. |z_1 z_2| = |z_1| \cdot |z_2|.

This is the key algebraic property. The modulus of a product is the product of the moduli. Here is the proof. Let z_1 = a + bi, z_2 = c + di.

|z_1 z_2|^2 = (z_1 z_2)\overline{(z_1 z_2)} = z_1 z_2 \bar{z_1}\bar{z_2} = (z_1 \bar{z_1})(z_2 \bar{z_2}) = |z_1|^2 |z_2|^2

Taking square roots of both sides: |z_1 z_2| = |z_1||z_2|.

Geometrically: multiplying by z_2 scales distances by a factor of |z_2|. So the distance of z_1 z_2 from the origin is |z_1| scaled by |z_2|.

4. Quotient rule. \left|\dfrac{z_1}{z_2}\right| = \dfrac{|z_1|}{|z_2|} (when z_2 \neq 0).

This follows from multiplicativity. Write z_1 = (z_1/z_2) \cdot z_2, so |z_1| = |z_1/z_2| \cdot |z_2|, giving |z_1/z_2| = |z_1|/|z_2|.

5. Power rule. |z^n| = |z|^n for any positive integer n.

Apply multiplicativity repeatedly: |z^n| = |z \cdot z \cdot \dots \cdot z| = |z|^n.

6. Modulus of the real and imaginary parts.

|\operatorname{Re}(z)| \leq |z| \qquad \text{and} \qquad |\operatorname{Im}(z)| \leq |z|.

Since |z|^2 = x^2 + y^2 \geq x^2, taking square roots gives |z| \geq |x|. Similarly |z| \geq |y|. The modulus is at least as large as either component — the hypotenuse is never shorter than a leg.

The triangle inequality

The most important inequality in complex analysis is:

Triangle inequality for complex numbers

For any two complex numbers z_1 and z_2,

|z_1 + z_2| \leq |z_1| + |z_2|.

Equality holds if and only if z_1 and z_2 point in the same direction from the origin (that is, one is a non-negative real multiple of the other).

The name comes from geometry. If you draw arrows from the origin to z_1, from z_1 to z_1 + z_2, and from the origin to z_1 + z_2, the three arrows form a triangle. The inequality says: the length of the third side (the direct path from origin to z_1 + z_2) is at most the sum of the other two sides (|z_1| + |z_2|, the detour through z_1).

Triangle inequality illustrated on the complex planeA complex plane showing three vectors forming a triangle. The first vector goes from the origin to z1 at (3, 1). The second vector goes from z1 to z1 plus z2 at (4, 4). The third vector, drawn in red, goes directly from the origin to z1 plus z2. The direct path (red) is shorter than the two-step path through z1. Labels show the lengths.ReIm0123412z₁ = 3 + iz₁+z₂ = 4 + 4i|z₁| = √10|z₂| = √10|z₁+z₂| = 4√2z₂ = 1 + 3i√10 + √10 ≈ 6.324√2 ≈ 5.66 ≤ 6.32 ✓
The triangle inequality in action. The two-step path from $O$ to $z_1$ to $z_1 + z_2$ has total length $|z_1| + |z_2| = \sqrt{10} + \sqrt{10} \approx 6.32$. The direct path from $O$ to $z_1 + z_2$ has length $|z_1 + z_2| = 4\sqrt{2} \approx 5.66$. The direct path is shorter — the inequality $|z_1 + z_2| \leq |z_1| + |z_2|$ holds.

Proof of the triangle inequality

The proof is algebraic and uses the identity |z|^2 = z\bar{z}.

Start with |z_1 + z_2|^2. Expand it:

|z_1 + z_2|^2 = (z_1 + z_2)\overline{(z_1 + z_2)} = (z_1 + z_2)(\bar{z_1} + \bar{z_2})
= z_1\bar{z_1} + z_1\bar{z_2} + z_2\bar{z_1} + z_2\bar{z_2}
= |z_1|^2 + z_1\bar{z_2} + \overline{z_1\bar{z_2}} + |z_2|^2

The middle two terms are z_1\bar{z_2} and its conjugate \overline{z_1\bar{z_2}}. A number plus its conjugate is twice its real part:

z_1\bar{z_2} + \overline{z_1\bar{z_2}} = 2\operatorname{Re}(z_1\bar{z_2})

Now use the fact that the real part of any complex number is at most its modulus: \operatorname{Re}(w) \leq |w|. Therefore:

2\operatorname{Re}(z_1\bar{z_2}) \leq 2|z_1\bar{z_2}| = 2|z_1||\bar{z_2}| = 2|z_1||z_2|

Putting it all together:

|z_1 + z_2|^2 \leq |z_1|^2 + 2|z_1||z_2| + |z_2|^2 = (|z_1| + |z_2|)^2

Taking square roots (both sides are non-negative):

|z_1 + z_2| \leq |z_1| + |z_2|

Equality holds when \operatorname{Re}(z_1\bar{z_2}) = |z_1\bar{z_2}|, which means z_1\bar{z_2} is a non-negative real number — equivalently, z_1 is a non-negative real multiple of z_2 (they point in the same direction).

The reverse triangle inequality

There is a companion result that bounds |z_1 + z_2| from below:

\bigl||z_1| - |z_2|\bigr| \leq |z_1 + z_2|

The proof: apply the triangle inequality to (z_1 + z_2) + (-z_2) = z_1 to get |z_1| \leq |z_1 + z_2| + |z_2|, so |z_1 + z_2| \geq |z_1| - |z_2|. Swapping the roles gives |z_1 + z_2| \geq |z_2| - |z_1|. Combining: |z_1 + z_2| \geq \bigl||z_1| - |z_2|\bigr|.

Together, the two inequalities give a two-sided bound:

\bigl||z_1| - |z_2|\bigr| \leq |z_1 + z_2| \leq |z_1| + |z_2|

The modulus of a sum is squeezed between the difference and the sum of the individual moduli.

The modulus as a circle

All complex numbers with the same modulus lie on a circle centred at the origin. The equation |z| = r describes a circle of radius r. In Cartesian terms, x^2 + y^2 = r^2.

More generally, |z - z_0| = r describes a circle of radius r centred at z_0. This is because |z - z_0| is the distance from z to z_0, and the set of all points at a fixed distance from a centre is a circle.

Circles of constant modulus on the complex planeA complex plane with three concentric circles centred at the origin, with radii 1, 2, and 3. Each circle is labelled with its modulus value. Several example complex numbers are marked on the circles: i on the unit circle, 1 plus root 3 i on the circle of radius 2, and 3 on the circle of radius 3.ReIm0|z|=1|z|=2|z|=3i1+√3 i3−√2+√7 i
Concentric circles of constant modulus. Every point on the inner circle has $|z| = 1$ — the unit circle. The number $i$ lives here (since $|i| = 1$). The number $1 + \sqrt{3}\,i$ lives on the circle $|z| = 2$ (since $|1 + \sqrt{3}\,i| = \sqrt{1 + 3} = 2$). The real number $3$ lives on $|z| = 3$.

Worked examples

Example 1: Find $|z|$ where $z = \dfrac{3 + 4i}{1 - 2i}$

Rather than dividing first, use the quotient rule for modulus.

Step 1. Compute |3 + 4i|.

|3 + 4i| = \sqrt{9 + 16} = \sqrt{25} = 5

Why: apply the definition directly. 3^2 + 4^2 = 25 is a Pythagorean triple, so the root is clean.

Step 2. Compute |1 - 2i|.

|1 - 2i| = \sqrt{1 + 4} = \sqrt{5}

Why: the imaginary part is -2, but its square is 4, same as for +2. The modulus does not care about the sign of the imaginary part.

Step 3. Apply the quotient rule.

\left|\frac{3 + 4i}{1 - 2i}\right| = \frac{|3 + 4i|}{|1 - 2i|} = \frac{5}{\sqrt{5}} = \frac{5\sqrt{5}}{5} = \sqrt{5}

Why: |z_1/z_2| = |z_1|/|z_2|. Rationalising the denominator gives \sqrt{5}.

Step 4. Verify by computing the quotient directly. From Division of Complex Numbers:

\frac{3 + 4i}{1 - 2i} = \frac{(3+4i)(1+2i)}{(1-2i)(1+2i)} = \frac{3+6i+4i+8i^2}{1+4} = \frac{-5+10i}{5} = -1 + 2i

And |-1 + 2i| = \sqrt{1 + 4} = \sqrt{5}. Confirmed.

Result: \left|\dfrac{3 + 4i}{1 - 2i}\right| = \sqrt{5}.

Modulus of a quotient: |3+4i| over |1−2i| gives the modulus of the quotientA complex plane with three points: 3 plus 4i in the first quadrant at distance 5 from the origin, 1 minus 2i in the fourth quadrant at distance root 5 from the origin, and the quotient negative 1 plus 2i in the second quadrant at distance root 5 from the origin. Circles of appropriate radii pass through each point.ReIm0123−1−212−1|z|=5|z|=√53+4i|z₁|=51−2i|z₂|=√5−1+2i|z₁/z₂|=√5
The dividend $3 + 4i$ has modulus $5$ (outer dashed circle). The divisor $1 - 2i$ has modulus $\sqrt{5}$. The quotient $-1 + 2i$ has modulus $5/\sqrt{5} = \sqrt{5}$ (inner red circle). Division shrinks the distance by a factor of $|z_2| = \sqrt{5}$.

The quotient rule saved a full division computation. When you only need the modulus of the result — not the result itself — working with moduli directly is faster.

Example 2: Prove that $|z_1 + z_2|^2 + |z_1 - z_2|^2 = 2(|z_1|^2 + |z_2|^2)$ and verify with $z_1 = 1 + i$, $z_2 = 2 - i$

This is the parallelogram law — the sum of the squares of the diagonals of a parallelogram equals the sum of the squares of all four sides.

Step 1. Expand |z_1 + z_2|^2.

|z_1 + z_2|^2 = (z_1 + z_2)(\bar{z_1} + \bar{z_2}) = |z_1|^2 + z_1\bar{z_2} + z_2\bar{z_1} + |z_2|^2

Why: |w|^2 = w\bar{w}, and the conjugate of a sum is the sum of the conjugates.

Step 2. Expand |z_1 - z_2|^2.

|z_1 - z_2|^2 = (z_1 - z_2)(\bar{z_1} - \bar{z_2}) = |z_1|^2 - z_1\bar{z_2} - z_2\bar{z_1} + |z_2|^2

Why: the cross terms pick up negative signs from the subtraction.

Step 3. Add the two expansions.

|z_1 + z_2|^2 + |z_1 - z_2|^2 = 2|z_1|^2 + 2|z_2|^2

The cross terms z_1\bar{z_2} + z_2\bar{z_1} cancel exactly.

Why: the cross terms appear with a + sign in the first expansion and a - sign in the second, so they vanish when added. This is the algebraic heart of the parallelogram law.

Step 4. Verify numerically. Take z_1 = 1 + i, z_2 = 2 - i.

z_1 + z_2 = 3, \qquad z_1 - z_2 = -1 + 2i
|z_1 + z_2|^2 = 9, \qquad |z_1 - z_2|^2 = 1 + 4 = 5
|z_1|^2 = 1 + 1 = 2, \qquad |z_2|^2 = 4 + 1 = 5

Left side: 9 + 5 = 14. Right side: 2(2 + 5) = 14. They match.

Result: |z_1 + z_2|^2 + |z_1 - z_2|^2 = 2(|z_1|^2 + |z_2|^2) for all complex z_1, z_2.

Parallelogram law: the two diagonals of the parallelogram formed by z1 and z2A complex plane showing a parallelogram with vertices at the origin, z1 equals 1 plus i, z2 equals 2 minus i, and z1 plus z2 equals 3. The two diagonals are drawn: one from the origin to z1 plus z2 (length 3) and one from z1 to z2 (which represents z1 minus z2, length root 5). The sides are drawn as solid lines.ReIm01231−1Oz₁=1+iz₂=2−iz₁+z₂=3|z₁+z₂|²=9|z₁−z₂|²=59 + 5 = 142(2 + 5) = 14 ✓
The parallelogram formed by $z_1 = 1 + i$ and $z_2 = 2 - i$. The red diagonal from $O$ to $z_1 + z_2 = 3$ has squared length $9$. The dashed diagonal from $z_1$ to $z_2$ has squared length $|z_1 - z_2|^2 = 5$. The parallelogram law says: $9 + 5 = 2(2 + 5) = 14$.

The parallelogram law is the complex version of a result from Euclidean geometry. It holds for all parallelograms, not just complex-number ones — but the algebraic proof with conjugates is one of the cleanest ways to see why it holds.

Common confusions

Going deeper

If you know the definition |z| = \sqrt{x^2 + y^2}, the connection |z|^2 = z\bar{z}, the multiplicativity |z_1 z_2| = |z_1||z_2|, and the triangle inequality with its proof, you have the full toolkit for the modulus. The material below is for readers who want to see the deeper structure.

The modulus as a norm

In linear algebra, a norm is a function that assigns a non-negative "size" to each vector in a vector space, satisfying three axioms:

  1. \|v\| \geq 0, with equality only for v = 0 (positive definiteness).
  2. \|\alpha v\| = |\alpha| \cdot \|v\| for any scalar \alpha (absolute homogeneity).
  3. \|u + v\| \leq \|u\| + \|v\| (triangle inequality).

The complex modulus satisfies all three, with \alpha being a real scalar and v being a complex number viewed as a vector in \mathbb{R}^2. So the modulus is a norm on the complex plane — it is the Euclidean norm, the same one you use to measure distances in ordinary two-dimensional space.

The modulus and Brahmagupta's identity

The multiplicativity |z_1 z_2| = |z_1||z_2| has a surprising consequence when written in terms of real and imaginary parts. If z_1 = a + bi and z_2 = c + di, then:

|z_1|^2 \cdot |z_2|^2 = |z_1 z_2|^2
(a^2 + b^2)(c^2 + d^2) = (ac - bd)^2 + (ad + bc)^2

This is Brahmagupta's identity: the product of two sums of two squares is itself a sum of two squares. Brahmagupta stated this result in the 7th century, and it follows naturally from the multiplicativity of the complex modulus — though complex numbers would not be formalised for another millennium. The identity is a beautiful example of a fact about real numbers that is most easily proved by passing through the complex numbers.

The unit circle and multiplication

The complex numbers with |z| = 1 form a group under multiplication. If |z_1| = 1 and |z_2| = 1, then |z_1 z_2| = |z_1||z_2| = 1, so the product also has modulus 1. Every such number can be written as \cos\theta + i\sin\theta for some angle \theta, and multiplication corresponds to adding the angles. This is the starting point for the polar form of complex numbers and for understanding complex multiplication as rotation.

Where this leads next

The modulus gives you the "size" of a complex number. The next steps are about direction and the full geometric picture.