In short

The unit circle lets you define \sin\theta and \cos\theta for every angle, not just acute ones. A point on a circle of radius 1 centred at the origin has coordinates (\cos\theta, \sin\theta). The sign of each ratio depends on which quadrant the angle lands in, and every angle shares its ratio values (up to sign) with a unique acute angle called the reference angle.

You know that \sin 30° = \tfrac{1}{2}. That comes from a right triangle with a 30° angle — the side opposite to 30° is half the hypotenuse, and there is nothing more to say.

But what is \sin 150°? You cannot draw a right triangle with an interior angle of 150° — no such triangle exists, because the angles of a triangle add to 180°, and a right angle already uses up 90° of that. The right-triangle definition of sine simply does not apply to 150°.

Yet your calculator will happily tell you that \sin 150° = 0.5. The same answer as \sin 30°. That is not a coincidence, and it is not a convention. There is a geometric reason — and to see it, you need a bigger definition of sine that works for every angle.

The unit circle

Take a circle of radius 1, centred at the origin of the coordinate plane. This is called the unit circle. Now pick any angle \theta, measured from the positive x-axis, and rotate counterclockwise by that amount. The ray from the origin at angle \theta hits the unit circle at exactly one point. Call that point P.

The unit circle with a point P at angle thetaA circle of radius 1 centred at the origin. A ray from the origin makes angle theta with the positive x-axis. The ray meets the circle at point P. A vertical line from P to the x-axis shows the y-coordinate (sin theta), and a horizontal line from the y-axis to P shows the x-coordinate (cos theta). x y P(cos θ, sin θ) sin θ cos θ θ 1 −1 1 −1
The unit circle. A ray from the origin at angle $\theta$ meets the circle at $P$. The $x$-coordinate of $P$ is $\cos\theta$; the $y$-coordinate is $\sin\theta$. The dashed lines show these coordinates as horizontal and vertical distances.

The point P has two coordinates. Define:

\cos\theta = \text{the } x\text{-coordinate of } P, \qquad \sin\theta = \text{the } y\text{-coordinate of } P

That is the entire definition. No triangle needed, no restriction on \theta. The angle can be 30°, 150°, -45°, 720°, or \pi/6 radians — the definition always works, because you can always draw a ray at that angle and read off coordinates.

Unit-circle definition of sine and cosine

If a ray from the origin makes angle \theta with the positive x-axis (measured counterclockwise), and this ray meets the unit circle at the point P, then

\cos\theta = x_P, \qquad \sin\theta = y_P

The other four ratios follow:

\tan\theta = \frac{\sin\theta}{\cos\theta}, \qquad \cot\theta = \frac{\cos\theta}{\sin\theta}, \qquad \sec\theta = \frac{1}{\cos\theta}, \qquad \csc\theta = \frac{1}{\sin\theta}

Why this agrees with the right-triangle definition. For an acute angle \theta, drop a perpendicular from P to the x-axis. You get a right triangle with hypotenuse 1 (the radius), adjacent side x_P, and opposite side y_P. The old definitions give \cos\theta = \text{adjacent}/\text{hypotenuse} = x_P/1 = x_P and \sin\theta = \text{opposite}/\text{hypotenuse} = y_P/1 = y_P. The unit circle definition produces the same numbers for acute angles — it is an extension, not a replacement.

Signs in the four quadrants

The unit circle makes the sign question mechanical. In each quadrant, the coordinates of P have definite signs, and those signs determine the signs of every trigonometric ratio.

Quadrant x-coordinate y-coordinate \cos\theta \sin\theta \tan\theta
I (0° < \theta < 90°) + + + + +
II (90° < \theta < 180°) - + - + -
III (180° < \theta < 270°) - - - - +
IV (270° < \theta < 360°) + - + - -

In Quadrant I, everything is positive. In Quadrant II, only sine is positive (the y-coordinate is positive, the x-coordinate is negative). In Quadrant III, only tangent is positive (both coordinates are negative, and a negative divided by a negative is positive). In Quadrant IV, only cosine is positive.

Indian textbooks often encode this as the mnemonic "All Students Take Coffee" — reading counterclockwise from Quadrant I: All, Sine, Tangent, Cosine. Each word names the ratio(s) that are positive in that quadrant.

Signs of trigonometric ratios in four quadrantsA diagram of the four quadrants, showing which trigonometric ratios are positive in each. Quadrant I: all positive. Quadrant II: sin positive. Quadrant III: tan positive. Quadrant IV: cos positive. x y I All + II sin + III tan + IV cos +
The ASTC rule: **A**ll ratios positive in I, **S**ine in II, **T**angent in III, **C**osine in IV. This is entirely determined by the signs of the $x$- and $y$-coordinates in each quadrant.

Reference angles

Here is the key insight: \sin 150° and \sin 30° have the same absolute value because the two points on the unit circle are mirror images of each other across the y-axis. The point at 150° has coordinates (-\cos 30°, \sin 30°). The sine (the y-coordinate) is the same; the cosine (the x-coordinate) just changes sign.

The acute angle that captures this relationship is called the reference angle.

Reference angle

For any angle \theta in standard position, the reference angle \alpha is the acute angle between the terminal side of \theta and the x-axis (not the y-axis). It is always between and 90°.

Quadrant Reference angle \alpha
I \alpha = \theta
II \alpha = 180° - \theta
III \alpha = \theta - 180°
IV \alpha = 360° - \theta

The trigonometric ratios of \theta equal the ratios of \alpha, up to sign — and the sign is determined by the quadrant.

This is why \sin 150° = \sin 30°. The angle 150° is in Quadrant II, so its reference angle is 180° - 150° = 30°. Sine is positive in Quadrant II. So \sin 150° = +\sin 30° = 1/2.

And \cos 150°? Cosine is negative in Quadrant II. So \cos 150° = -\cos 30° = -\sqrt{3}/2.

Reference angle for 150 degreesThe unit circle with two rays from the origin. One ray is at 30 degrees (in Quadrant I), the other at 150 degrees (in Quadrant II). Both rays meet the circle at points that have the same y-coordinate but opposite x-coordinates, illustrating that sin 150 degrees equals sin 30 degrees. P₁ (30°) P₂ (150°) 30° 30° same height
The points at $30°$ and $150°$ sit at the same height on the unit circle — same $y$-coordinate, opposite $x$-coordinates. The reference angle for $150°$ is $180° - 150° = 30°$. This is why $\sin 150° = \sin 30°$ and $\cos 150° = -\cos 30°$.

The reference angle reduces every problem about arbitrary angles to a problem about acute angles — angles whose values you already know from the standard table (, 30°, 45°, 60°, 90°).

Here is the full procedure: given any angle \theta, find its trigonometric ratios in three steps.

  1. Find the quadrant that \theta lands in.
  2. Find the reference angle \alpha using the table above.
  3. Write the ratio of \alpha, and attach the sign from the ASTC rule.

Take \theta = 225°. This is in Quadrant III (between 180° and 270°). The reference angle is 225° - 180° = 45°. In Quadrant III, sine and cosine are both negative, and tangent is positive. So:

\sin 225° = -\sin 45° = -\frac{\sqrt{2}}{2}, \qquad \cos 225° = -\cos 45° = -\frac{\sqrt{2}}{2}, \qquad \tan 225° = +\tan 45° = 1

Check: \tan 225° = \sin 225° / \cos 225° = (-\sqrt{2}/2) / (-\sqrt{2}/2) = 1. Consistent.

Here is a picture showing the reference angles for all four quadrants, using the same base angle \alpha = 30°:

Reference angles in all four quadrants for base angle 30 degreesThe unit circle with four rays from the origin at 30, 150, 210, and 330 degrees. Each ray has the same reference angle of 30 degrees with the x-axis, shown as a small arc near the axis. This illustrates that all four angles share the same magnitude of trig ratios, differing only in sign. 30° 150° 210° 330° 30° 30° 30° 30°
Four angles with the same reference angle of $30°$: at $30°$, $150°$, $210°$, and $330°$. All four share the same $|\sin|$ and $|\cos|$ values — $1/2$ and $\sqrt{3}/2$ — but with different signs determined by the quadrant.

Allied angles

Angles that differ by multiples of 90° have a systematic relationship. These are called allied angles (or associated angles). The relationships come directly from the unit circle — from the symmetry of a circle about its axes and diagonals.

Here are the key identities. Each one can be read off the unit circle by reflecting or rotating the point P.

Supplementary angles (180° - \theta): the point reflects across the y-axis.

\sin(180° - \theta) = \sin\theta, \qquad \cos(180° - \theta) = -\cos\theta, \qquad \tan(180° - \theta) = -\tan\theta

Anti-supplementary angles (180° + \theta): the point reflects through the origin.

\sin(180° + \theta) = -\sin\theta, \qquad \cos(180° + \theta) = -\cos\theta, \qquad \tan(180° + \theta) = \tan\theta

Negative angles (-\theta or equivalently 360° - \theta): the point reflects across the x-axis.

\sin(-\theta) = -\sin\theta, \qquad \cos(-\theta) = \cos\theta, \qquad \tan(-\theta) = -\tan\theta

Complementary shifts (90° - \theta): this is the one where sine and cosine swap.

\sin(90° - \theta) = \cos\theta, \qquad \cos(90° - \theta) = \sin\theta

The co-function shift (90° + \theta): the point rotates 90° counterclockwise.

\sin(90° + \theta) = \cos\theta, \qquad \cos(90° + \theta) = -\sin\theta

There is a pattern hiding here. When the allied angle involves 180° or 360° (even multiples of 90°), the function name stays the same — sine stays sine, cosine stays cosine. When the allied angle involves 90° or 270° (odd multiples of 90°), the function name switches — sine becomes cosine and cosine becomes sine. The sign is then determined by which quadrant the original expression lands in.

Why does the 90° shift swap sine and cosine? On the unit circle, rotating a point by 90° counterclockwise sends (x, y) to (-y, x). The old y-coordinate (sine) becomes the new x-coordinate (cosine), and vice versa. The swap is geometric — it comes from what a 90° rotation does to coordinates.

Proof of \sin(180° - \theta) = \sin\theta. The point at angle \theta has coordinates (\cos\theta, \sin\theta). The point at angle 180° - \theta is the reflection of this point across the y-axis — it has coordinates (-\cos\theta, \sin\theta). The y-coordinate is \sin\theta in both cases. So \sin(180° - \theta) = \sin\theta.

Proof of \cos(180° + \theta) = -\cos\theta. The point at 180° + \theta is diametrically opposite the point at \theta on the unit circle. If \theta gives the point (\cos\theta, \sin\theta), then 180° + \theta gives (-\cos\theta, -\sin\theta). Read off the x-coordinate: \cos(180° + \theta) = -\cos\theta.

Computing ratios: two worked examples

Example 1: Find all six trigonometric ratios of 210°

Step 1. Identify the quadrant. Since 180° < 210° < 270°, the angle is in Quadrant III.

Why: the quadrant tells you the signs. In Quadrant III, x < 0 and y < 0, so \cos and \sin are both negative, while \tan is positive.

Step 2. Find the reference angle. For Quadrant III: \alpha = 210° - 180° = 30°.

Why: the reference angle is always measured from the nearest part of the x-axis, giving an acute angle whose ratio values you know from the standard table.

Step 3. Write the ratios of 30° with the correct signs.

\sin 210° = -\sin 30° = -\frac{1}{2}, \qquad \cos 210° = -\cos 30° = -\frac{\sqrt{3}}{2}
\tan 210° = +\tan 30° = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}

Why: in Quadrant III, only tangent is positive (the "T" in ASTC).

Step 4. Compute the reciprocal ratios.

\csc 210° = \frac{1}{\sin 210°} = -2, \qquad \sec 210° = \frac{1}{\cos 210°} = -\frac{2}{\sqrt{3}} = -\frac{2\sqrt{3}}{3}
\cot 210° = \frac{1}{\tan 210°} = \sqrt{3}

Why: each reciprocal ratio is just the reciprocal of the corresponding primary ratio, inheriting the same sign.

Result: \sin 210° = -\tfrac{1}{2}, \cos 210° = -\tfrac{\sqrt{3}}{2}, \tan 210° = \tfrac{\sqrt{3}}{3}, \csc 210° = -2, \sec 210° = -\tfrac{2\sqrt{3}}{3}, \cot 210° = \sqrt{3}.

The angle 210 degrees on the unit circleThe unit circle with a ray from the origin at 210 degrees, in Quadrant III. The point P on the circle is at coordinates (negative root 3 over 2, negative one half). A dashed line shows the reference angle of 30 degrees between the ray and the negative x-axis. P(−√3/2, −1/2) 30° ref. angle
The angle $210°$ on the unit circle. The ray is in Quadrant III. The reference angle — the angle between the ray and the negative $x$-axis — is $30°$. The coordinates of $P$ confirm all six ratios.

The picture confirms the computation: P is below and to the left of the origin, so both coordinates are negative. The reference triangle in Quadrant III is a 30-60-90 triangle reflected into the third quadrant.

Example 2: Find sin(−135°)

Step 1. Interpret the negative angle. A negative angle means clockwise rotation. Starting from the positive x-axis and rotating 135° clockwise takes you to the same position as 360° - 135° = 225°.

Why: adding 360° to any angle does not change the position on the unit circle. So -135° and 225° are the same point.

Step 2. Identify the quadrant. The angle 225° is in Quadrant III (between 180° and 270°).

Why: in Quadrant III, both coordinates are negative, so \sin is negative.

Step 3. Find the reference angle. \alpha = 225° - 180° = 45°.

Why: we subtract 180° because the angle is in Quadrant III.

Step 4. Apply the sign. Sine is negative in Quadrant III.

\sin(-135°) = \sin 225° = -\sin 45° = -\frac{\sqrt{2}}{2}

Why: the reference angle gives the magnitude (\sin 45° = \sqrt{2}/2), and the quadrant gives the sign (negative).

Result: \sin(-135°) = -\dfrac{\sqrt{2}}{2}.

The angle negative 135 degrees on the unit circleThe unit circle with a ray from the origin at negative 135 degrees, which is the same as 225 degrees. The ray is in Quadrant III, and the point P is at coordinates (negative root 2 over 2, negative root 2 over 2). A curved arrow shows the clockwise rotation of 135 degrees. P(−√2/2, −√2/2) −135° (clockwise)
Rotating $135°$ clockwise from the positive $x$-axis lands at $225°$ counterclockwise. The point $P$ in Quadrant III has both coordinates negative, confirming $\sin(-135°) = -\sqrt{2}/2$.

Two things to notice. First, the negative angle is just a direction of rotation — it does not mean the sine is negative (though in this case it happens to be). Second, you can always convert a negative angle to a positive one by adding 360°, then use the standard reference-angle procedure.

The ratios at the axes

What about angles that land exactly on an axis — , 90°, 180°, 270°? These are not in any quadrant, and they give rise to the boundary values.

At , the point on the unit circle is (1, 0). So \cos 0° = 1 and \sin 0° = 0.

At 90°, the point is (0, 1). So \cos 90° = 0 and \sin 90° = 1. Since \tan 90° = \sin 90° / \cos 90° = 1/0, tangent is undefined at 90°.

At 180°, the point is (-1, 0). So \cos 180° = -1 and \sin 180° = 0.

At 270°, the point is (0, -1). So \cos 270° = 0 and \sin 270° = -1.

These boundary values are worth memorising alongside the standard table. They come up constantly — especially \sin 90° = 1, \cos 90° = 0, and the fact that \tan 90° does not exist.

Common confusions

Going deeper

If you came here to learn how sine and cosine extend beyond acute angles, you have it — you can stop here. The rest is for readers who want a tighter algebraic framework for allied angles and a connection to the coordinate-geometry definition of angle.

A general formula for allied angles

Every allied angle has the form n \cdot 90° \pm \theta, where n is an integer. The rule is:

In both cases, the sign on the right is determined by checking what sign the original function (the one on the left) would have in the quadrant where n \cdot 90° \pm \theta falls, assuming \theta is acute.

This single rule generates every identity in the allied-angles table — all sixteen entries. It is worth understanding the rule rather than memorising the table, because the rule can be reconstructed from the unit circle in thirty seconds, while the table cannot.

Why 360° is special

Adding 360° to any angle brings the point back to the same position on the unit circle. This means \sin(\theta + 360°) = \sin\theta and \cos(\theta + 360°) = \cos\theta for every \theta. The number 360° (or 2\pi in radians) is the period of sine and cosine.

Tangent has a shorter period: \tan(\theta + 180°) = \tan\theta. This is because the point at \theta + 180° is diametrically opposite the point at \theta, so both coordinates flip sign — and the ratio of two negatives is positive. You will explore this periodicity in detail in Trigonometric Functions and Graphs.

Angles beyond 360° and in radians

The unit-circle definition handles angles of any size without modification. An angle of 750° means rotating counterclockwise by 750° = 2 \times 360° + 30°, which is two full revolutions plus 30°. The terminal point lands at the same position as 30°, so \sin 750° = \sin 30° = 1/2.

In radians, 180° = \pi. All the identities above hold with \pi replacing 180° and \pi/2 replacing 90°. For instance, \sin(\pi - \theta) = \sin\theta. The radian version is what you will use in calculus and in the study of Trigonometric Functions and Graphs.

Where this leads next

The unit circle is the launchpad for everything that follows in trigonometry.